James Bond: 20 units, two thirds of the table.
The most famous “movie” system was invented by Ian Fleming in the novel Casino Royale. One fixed ticket — 14 units on the high numbers, 5 on the six line 13–18 and 1 on the zero — covers 25 of the 37 numbers. It sounds excellent until you work out what the other twelve cost. Here you can take the system apart step by step and test it on simulated spins.
Test James Bond on your own bankroll
Set the bankroll, the value of a unit and the number of spins. The simulator shows how the bankroll develops, breaks the hits down by bet type, and shows what a run of numbers from 1–12 does to the ticket.
Bankroll and ticket
Variant and wheel
The ticket covers 25 numbers including the zero; the double zero on American roulette is not covered. Every run uses a fresh random sequence of spins.
Bankroll over time
Two thirds of spins bring a small profit — but every first-dozen result cuts a −20-unit step downward.
What happened in the simulation: Click "Run the simulation" and you will get a short, plain-language explanation of the result here.
Three bets, one 20-unit ticket
James Bond does not bet on one spot. It spreads a fixed ticket to cover as many numbers as possible — and each type of hit returns a different profit.
What one spin does to the ticket
The three winning scenarios look generous, but the arithmetic is settled: twelve uncovered numbers take the whole ticket and pull the average down to exactly −2.70% of the stake.
The ticket: three bets for 20 units
The spread is always the same — which is what makes James Bond a flat system. The payouts of the individual bets are arranged so that every hit ends in profit.
The covered numbers on the roulette layout
The gold-outlined numbers are the ones the ticket backs. The label in the corner shows how many units that bet carries as a whole. The only losing zone is the first dozen, 1–12.
What will a session of James Bond cost you?
This calculator is not about a single spin. It shows what you pay on average for a whole evening, what chance you have of finishing ahead — and how likely the run of first-dozen results that hurts the ticket most really is.
Enter a unit value and a session length. The result shows the average cost of the evening, the chance of finishing ahead and the probability of a longer losing run.
Is James Bond a good roulette system?
The best marketing in the history of roulette systems — and a textbook demonstration that even covering two thirds of the table does not beat the maths. Here is the whole story, and the numbers.
What is the James Bond system?
James Bond is a roulette strategy described by Ian Fleming — the creator of Bond — in the 1953 novel Casino Royale. Fleming presented it as a sensible way of winning the price of a good dinner on a capital of ten pounds. Unlike most systems it is not a progression: you always bet the same twenty-unit ticket, split across three spots so that it covers 25 of the 37 numbers of the European wheel.
That simplicity and cinematic origin are exactly what made it one of the most searched-for systems of all. It is easy to remember, needs no counting during play, and wins most spins. But “wins most spins” and “makes money” are two entirely different things — and the gap between them is precisely what this page shows.
How James Bond is bet
The ticket always has the same three parts. Fourteen units go on the high numbers 19–36 — an even-money bet paying 1:1. Five units on the six line 13–18, six numbers paying 5:1. And one unit on the zero at 35:1, which works as insurance against the green pocket.
The charm of the spread is that every hit ends in profit: the high numbers earn +8 units (14 won minus 6 lost), the six line +10 (25 won minus 15) and the zero as much as +16 (35 won minus 19). You lose only when a number from the first dozen lands — and then the whole twenty-unit ticket vanishes at once.
Why it feels bulletproof
The system wins roughly two spins in three. Psychologically that is a very powerful experience: wins come often, losses look like bad luck, and the player feels it “works”. Frequent small profits create the same illusion of control as the Bally system or other broad-coverage bets.
But the long-term result is not decided by how often you win — it is decided by the ratio between the small win and the large loss. The average hit returns about +8.8 units, but it arrives with a probability of 67.6%. The −20-unit loss arrives in the remaining 32.4% of cases. Multiply it out and you get exactly −0.54 units per spin. No arrangement of chips changes that average.
What exactly does the house edge mean for James Bond?
The house edge is built into the ratio of payouts to probabilities of each individual bet. The high numbers, the six line and the zero each have an expected value of −2.70% on their own — and so does their sum. Spreading the ticket cannot “compensate” for anything: you are combining three negative bets, and the result is negative again.
On American roulette it is worse still. The double zero is not covered, so there are thirteen losing numbers instead of twelve — and because the payouts stay the same, the expected loss doubles to −1.05 units per spin. If you are going to try James Bond at all, do it on a European wheel.
Variants of the James Bond system
The most common adjustment is the “progressive Bond”: double the whole ticket after a loss and return to the base after a win. It sounds like a quick way to make a first-dozen result back — in reality you have just invented Martingale with a base bet twenty times as large. Three losses in a row and you are betting 160 units a spin, with the bankroll disappearing at a dizzying rate. You can switch exactly this variant on in the simulator above and watch how dramatically it changes the character of the chart.
The second adjustment people discuss is dropping the zero (a “cheaper 19-unit ticket”). That is a worse idea still: the zero then loses the whole ticket and the expected loss per spin gets worse. The single unit on the zero is not a luxury, it is the cheapest part of the ticket — without it the system loses even the little elegance it has.
The biggest risks and limits
The main risk of James Bond is inconspicuous: cost per spin. A 20-unit ticket means that even a “small” $10 unit works out at $200 a spin — at sixty spins an hour you stake $12,000 every hour. The system does not explode the way Martingale does; it drains steadily, half a unit per spin on average.
The second risk is runs of first-dozen results. Odds of 32.4% mean two losses in a row turn up in roughly every tenth pair of spins, and three in a row have a 3.4% chance. Over hundreds of spins a run of four or even five losses is close to certain — that is −80 to −100 units in a few minutes. Anyone without a reserve for it is finished before the “stability” of the system ever shows.
How to read the bankroll chart
The classic Bond chart is a jagged, gently falling saw: plenty of small steps up (+8, +10, occasionally +16) and regular deeper steps down (−20). No dramatic collapses — just a persistent slide at a gradient of −0.54 units per spin. The longer the test, the more clearly the curve follows that straight line.
Switch the simulator to the aggressive variant and the shape becomes unrecognisable: long calm stretches and occasional steep plunges, exactly like Martingale. The “Ticket size” toggle shows you why — after losses the ticket grows geometrically and the bankroll stops keeping up.
How to use James Bond sensibly in the tester
One simulation run is just one random history. You will learn far more from the Roulette system tester, where James Bond is preloaded and you can run it over 100 or 500 independent runs at once: you will see what percentage of runs end ahead, what the median result is, and how wide the band between lucky and unlucky evenings really is.
The typical result over a thousand spins: almost no ruin (the system does not escalate), but only a fraction of runs ahead and a median noticeably below the starting point. That is exactly the signature of a flat system with a negative expectation — no drama, just a slow, reliable decline.
The verdict: is James Bond usable?
As entertainment, yes — and frankly it is one of the most enjoyable systems to play. The wins come often, you can memorise the rules in a minute, and the Bond story adds charm. Taken as paid entertainment with a firm limit, it is a legitimate way to enjoy roulette.
As a way of making money, no. An expected loss of −2.70% on every ticket is a mathematical fact no arrangement of chips changes. The greatest value of James Bond is educational: it shows beautifully that covering two thirds of the table is not an edge — only another way of paying the same tax.
The biggest misconceptions about the James Bond system
The cinematic origin and the high coverage invite quick conclusions. Here are the most common myths, explained so a beginner can follow them.
Hits of +8 and +10 units come often, but a loss takes −20 at once. The ratio is arranged so the average works out at −2.70% — exactly as with every other bet.
Fleming invented the system as a comprehensible story for a novel. Casino Royale is not a mathematical proof — and even in the book Bond does not beat the casino long term by arranging chips.
The zero protects against one particular pocket, not against the twelve numbers of the first dozen. The “insurance” eases the pain of the green pocket but changes nothing about the negative average overall.
Doubling a twenty-unit ticket grows brutally fast: 20 → 40 → 80 → 160 units. Three first-dozen results in a row (a 3.4% chance) mean betting $1,600 at a $10 unit.
James Bond vs. other roulette systems
A flat spread is the exception among progressions — which makes it all the clearer that the problem is not the progression but the mathematics of roulette itself.
| System | Risk | Principle | Best for |
|---|---|---|---|
| Martingale | Very high | Doubling the bet after a loss | Understanding the risk of a progression |
| Fibonacci | High | A progression following the Fibonacci sequence | A slower progression after a loss |
| d'Alembert | Medium | +1 unit after a loss, −1 after a win | The gentlest progression |
| Labouchere | High | A cancellation line; the bet is first + last | More advanced players and experiments |
| Parlay | Medium | The win stays in play (let it ride) | Short runs after a win |
| 1-3-2-6 | Medium | The positive 1-3-2-6 progression after wins | A calmer game riding a winning wave |
| James Bond | Low to medium | A flat 20-unit ticket on 25 numbers | Broad coverage with no progression |
| Bally | Very high | 24 numbers with a 12–36–108–324 progression | Blanket bets with a harsh progression |
| Seven Corners | Medium | Seven corner bets, 27–28 numbers flat | Blanket bets with no progression |
| System 300 | Very high | 34 of 37 numbers, a rare 300-unit loss | Understanding asymmetric risk |
| John Wayne | High | A spread of 18 numbers for 10 units | Combined bets on numbers |
| Holy Grail | High | 18 distinct numbers with a progression | Covering half the wheel |
The name of a system takes you to its page with an interactive test — the current system is highlighted. Want to compare several systems on the exact same sequence of spins? Use the Roulette system tester.
Common questions about the James Bond system
Is the James Bond system profitable?
Not in the long run. Even though it covers 25 numbers and wins two spins in three, the expected value is −2.70% of every ticket — the occasional 20-unit loss outweighs the frequent small wins.
How exactly is James Bond bet?
Always the same 20-unit ticket: 14 units on the high numbers 19–36, 5 units on the six line 13–18 and 1 unit on the zero. The spread never changes.
Where does the system come from?
Ian Fleming, the creator of James Bond, described it in the novel Casino Royale (1953). It is a literary story rather than a mathematically verified strategy — which is exactly what made it the most famous “movie” system.
How many numbers does James Bond cover?
On European roulette, 25 of 37 numbers — roughly 67.6%. It loses only on the numbers 1–12. On American roulette the coverage is 25 of 38, because the double zero is not covered.
What does one spin cost?
Always 20 units. At a $10 unit that is $200 a spin — over an hour of live roulette (~60 spins) you stake around $12,000 and hand over roughly $320 of it on average.
Does James Bond work on American roulette?
Considerably worse. The double zero is not covered, there are 13 losing numbers instead of 12, and the average loss per spin doubles from −0.54 to −1.05 units. If at all, then only on a European wheel.
What if I double the whole ticket after a loss?
You create a Martingale with a 20-unit base: 20 → 40 → 80 → 160. Three losses in a row have a 3.4% chance and mean betting eight times the base. You can switch this variant on in the simulator on this page and compare the charts.
What bankroll do I need for James Bond?
A sensible minimum is 50–100 tickets, so 1,000 to 2,000 units. The system does not escalate, but a run of first-dozen results (−20 units a spin) can carve off hundreds of units in a few minutes.
Is James Bond better than a colour bet?
Mathematically they are identical: both have an EV of −2.70%. They differ only in the experience — Bond wins more often, but at a higher price. The choice is purely about which rhythm of play you find more pleasant.
Does James Bond change roulette’s house edge?
No. Each of the ticket’s three bets has a negative expected value, and so does their sum. Arranging chips changes the distribution of results over time, not their average.
Related tools and systems
First understand the principle, then work out the risk — and test longer scenarios over thousands of spins.