Roulette systems

James Bond: 20 units, two thirds of the table.

The most famous “movie” system was invented by Ian Fleming in the novel Casino Royale. One fixed ticket — 14 units on the high numbers, 5 on the six line 13–18 and 1 on the zero — covers 25 of the 37 numbers. It sounds excellent until you work out what the other twelve cost. Here you can take the system apart step by step and test it on simulated spins.

Type of systemA flat spread of betsA fixed 20-unit ticket (14 + 5 + 1), with no progression.
Coverage25 of 37 numbersA hit on roughly 67.57% of spins on European roulette.
RiskLow to mediumThe bet never grows — but every miss costs the full 20 units.
House edgeThe system does not change it2.70% (EU) / 5.26% (US) stays exactly the same.
1Bet 20 units14 on 19–36, 5 on the six line 13–18, 1 on the zero.
219–36 lands → +8The high numbers pay 1:1; the rest of the ticket loses.
313–18 lands → +10The six line pays 5:1 — the best ordinary hit.
40 lands → +16The “insurance” on the zero pays 35:1.
51–12 lands → −20A single loss — and it wipes out more than two hits.
Interactive simulator

Test James Bond on your own bankroll

Set the bankroll, the value of a unit and the number of spins. The simulator shows how the bankroll develops, breaks the hits down by bet type, and shows what a run of numbers from 1–12 does to the ticket.

Bankroll and ticket

The ticket costs 20 units, so one spin costs 20× the unit value.

Variant and wheel

The ticket covers 25 numbers including the zero; the double zero on American roulette is not covered. Every run uses a fresh random sequence of spins.

Deepest drawdown–maximum drawdown
Hits–high · six line · zero
Longest 1–12 run–losses in a row
Status–result of the run
Final bankroll–after the simulation
Spins played–before the test ended

Bankroll over time

Two thirds of spins bring a small profit — but every first-dozen result cuts a −20-unit step downward.

bankroll starting bankroll

What happened in the simulation: Click "Run the simulation" and you will get a short, plain-language explanation of the result here.

The spread of the ticket

Three bets, one 20-unit ticket

James Bond does not bet on one spot. It spreads a fixed ticket to cover as many numbers as possible — and each type of hit returns a different profit.

What one spin does to the ticket

EV = (18·8 + 6·10 + 1·16 − 12·20) / 37 ≈ −0.54 u.

The three winning scenarios look generous, but the arithmetic is settled: twelve uncovered numbers take the whole ticket and pull the average down to exactly −2.70% of the stake.

19–36 lands (odds 48.65%)+8 units
13–18 lands (odds 16.22%)+10 units
0 lands (odds 2.70%)+16 units
1–12 lands (odds 32.43%)−20 units

The ticket: three bets for 20 units

The spread is always the same — which is what makes James Bond a flat system. The payouts of the individual bets are arranged so that every hit ends in profit.

High numbers 19–36 (pays 1:1)14 units
Six line 13–18 (pays 5:1)5 units
Zero (pays 35:1)1 unit
Total per spin20 units

The covered numbers on the roulette layout

The gold-outlined numbers are the ones the ticket backs. The label in the corner shows how many units that bet carries as a whole. The only losing zone is the first dozen, 1–12.

covered number red number zero (covered)
Session calculator

What will a session of James Bond cost you?

This calculator is not about a single spin. It shows what you pay on average for a whole evening, what chance you have of finishing ahead — and how likely the run of first-dozen results that hurts the ticket most really is.

Result
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Enter a unit value and a session length. The result shows the average cost of the evening, the chance of finishing ahead and the probability of a longer losing run.

The complete guide

Is James Bond a good roulette system?

The best marketing in the history of roulette systems — and a textbook demonstration that even covering two thirds of the table does not beat the maths. Here is the whole story, and the numbers.

What is the James Bond system?

James Bond is a roulette strategy described by Ian Fleming — the creator of Bond — in the 1953 novel Casino Royale. Fleming presented it as a sensible way of winning the price of a good dinner on a capital of ten pounds. Unlike most systems it is not a progression: you always bet the same twenty-unit ticket, split across three spots so that it covers 25 of the 37 numbers of the European wheel.

That simplicity and cinematic origin are exactly what made it one of the most searched-for systems of all. It is easy to remember, needs no counting during play, and wins most spins. But “wins most spins” and “makes money” are two entirely different things — and the gap between them is precisely what this page shows.

The most important sentence on this pageJames Bond does not improve the chance of a covered number landing. High coverage only means you pay 20 units for every spin — and the 32% of spins where 1–12 lands take them all at once.

How James Bond is bet

The ticket always has the same three parts. Fourteen units go on the high numbers 19–36 — an even-money bet paying 1:1. Five units on the six line 13–18, six numbers paying 5:1. And one unit on the zero at 35:1, which works as insurance against the green pocket.

The charm of the spread is that every hit ends in profit: the high numbers earn +8 units (14 won minus 6 lost), the six line +10 (25 won minus 15) and the zero as much as +16 (35 won minus 19). You lose only when a number from the first dozen lands — and then the whole twenty-unit ticket vanishes at once.

Why it feels bulletproof

The system wins roughly two spins in three. Psychologically that is a very powerful experience: wins come often, losses look like bad luck, and the player feels it “works”. Frequent small profits create the same illusion of control as the Bally system or other broad-coverage bets.

But the long-term result is not decided by how often you win — it is decided by the ratio between the small win and the large loss. The average hit returns about +8.8 units, but it arrives with a probability of 67.6%. The −20-unit loss arrives in the remaining 32.4% of cases. Multiply it out and you get exactly −0.54 units per spin. No arrangement of chips changes that average.

A stop for the maths The maths of a single ticket The four possible outcomes of a spin, their probabilities and the net profit of each. This view shows why the system feels safe while remaining a loser on average.
Outcome probabilities (European roulette) p(19–36) = 18/37  ·  p(13–18) = 6/37  ·  p(0) = 1/37  ·  p(1–12) = 12/37 Twenty-five numbers win; twelve lose the whole ticket.
Expected value of a single spin EV = (18·8 + 6·10 + 1·16 − 12·20) / 37 = −20/37 ≈ −0.54 u. −0.54 units out of the 20 staked = exactly −2.70%. The same house edge as a plain colour bet.
European roulette−0.54 u. / spin−2.70% of a 20-unit ticket.
American roulette−1.05 u. / spinThe double zero is not covered — the loss doubles to −5.26%.
The key takeawayEV < 0High coverage changes the experience, not the average.
A concrete example A $10 unit — $200 per spin It shows the ratio between the frequent small profit and the less frequent but large loss.
19–36 lands+$80
13–18 lands+$100
0 lands+$160
1–12 lands−$200
Average over 100 spins−$541
Over a hundred spins you stake $20,000 and hand the casino $541 of it on average. One first-dozen result wipes out more than two average hits — and they land on roughly every third spin.
Chance of a hit≈ 67.57%25 covered numbers out of 37.
Chance of −$200≈ 32.43%The numbers 1–12 take the whole ticket.
Three first-dozen results in a row≈ 3.41%−$600 across three spins — routine, not a rarity.

What exactly does the house edge mean for James Bond?

The house edge is built into the ratio of payouts to probabilities of each individual bet. The high numbers, the six line and the zero each have an expected value of −2.70% on their own — and so does their sum. Spreading the ticket cannot “compensate” for anything: you are combining three negative bets, and the result is negative again.

On American roulette it is worse still. The double zero is not covered, so there are thirteen losing numbers instead of twelve — and because the payouts stay the same, the expected loss doubles to −1.05 units per spin. If you are going to try James Bond at all, do it on a European wheel.

Variants of the James Bond system

The most common adjustment is the “progressive Bond”: double the whole ticket after a loss and return to the base after a win. It sounds like a quick way to make a first-dozen result back — in reality you have just invented Martingale with a base bet twenty times as large. Three losses in a row and you are betting 160 units a spin, with the bankroll disappearing at a dizzying rate. You can switch exactly this variant on in the simulator above and watch how dramatically it changes the character of the chart.

The second adjustment people discuss is dropping the zero (a “cheaper 19-unit ticket”). That is a worse idea still: the zero then loses the whole ticket and the expected loss per spin gets worse. The single unit on the zero is not a luxury, it is the cheapest part of the ticket — without it the system loses even the little elegance it has.

The biggest risks and limits

The main risk of James Bond is inconspicuous: cost per spin. A 20-unit ticket means that even a “small” $10 unit works out at $200 a spin — at sixty spins an hour you stake $12,000 every hour. The system does not explode the way Martingale does; it drains steadily, half a unit per spin on average.

The second risk is runs of first-dozen results. Odds of 32.4% mean two losses in a row turn up in roughly every tenth pair of spins, and three in a row have a 3.4% chance. Over hundreds of spins a run of four or even five losses is close to certain — that is −80 to −100 units in a few minutes. Anyone without a reserve for it is finished before the “stability” of the system ever shows.

How to read the bankroll chart

The classic Bond chart is a jagged, gently falling saw: plenty of small steps up (+8, +10, occasionally +16) and regular deeper steps down (−20). No dramatic collapses — just a persistent slide at a gradient of −0.54 units per spin. The longer the test, the more clearly the curve follows that straight line.

Switch the simulator to the aggressive variant and the shape becomes unrecognisable: long calm stretches and occasional steep plunges, exactly like Martingale. The “Ticket size” toggle shows you why — after losses the ticket grows geometrically and the bankroll stops keeping up.

How to use James Bond sensibly in the tester

One simulation run is just one random history. You will learn far more from the Roulette system tester, where James Bond is preloaded and you can run it over 100 or 500 independent runs at once: you will see what percentage of runs end ahead, what the median result is, and how wide the band between lucky and unlucky evenings really is.

The typical result over a thousand spins: almost no ruin (the system does not escalate), but only a fraction of runs ahead and a median noticeably below the starting point. That is exactly the signature of a flat system with a negative expectation — no drama, just a slow, reliable decline.

The verdict: is James Bond usable?

As entertainment, yes — and frankly it is one of the most enjoyable systems to play. The wins come often, you can memorise the rules in a minute, and the Bond story adds charm. Taken as paid entertainment with a firm limit, it is a legitimate way to enjoy roulette.

As a way of making money, no. An expected loss of −2.70% on every ticket is a mathematical fact no arrangement of chips changes. The greatest value of James Bond is educational: it shows beautifully that covering two thirds of the table is not an edge — only another way of paying the same tax.

Myths and reality

The biggest misconceptions about the James Bond system

The cinematic origin and the high coverage invite quick conclusions. Here are the most common myths, explained so a beginner can follow them.

Myth: it covers 2/3 of the table, so it must make money.Reality: one first-dozen result wipes out more than two hits.

Hits of +8 and +10 units come often, but a loss takes −20 at once. The ratio is arranged so the average works out at −2.70% — exactly as with every other bet.

Myth: James Bond played it, so it works.Reality: it is literary fiction from 1953.

Fleming invented the system as a comprehensible story for a novel. Casino Royale is not a mathematical proof — and even in the book Bond does not beat the casino long term by arranging chips.

Myth: the unit on the zero makes the system safe.Reality: it is merely the cheapest part of the ticket.

The zero protects against one particular pocket, not against the twelve numbers of the first dozen. The “insurance” eases the pain of the green pocket but changes nothing about the negative average overall.

Myth: I double the ticket after a loss and I am back.Reality: you have just invented a 40-unit Martingale.

Doubling a twenty-unit ticket grows brutally fast: 20 → 40 → 80 → 160 units. Three first-dozen results in a row (a 3.4% chance) mean betting $1,600 at a $10 unit.

Comparing systems

James Bond vs. other roulette systems

A flat spread is the exception among progressions — which makes it all the clearer that the problem is not the progression but the mathematics of roulette itself.

SystemRiskPrincipleBest for
MartingaleVery highDoubling the bet after a lossUnderstanding the risk of a progression
FibonacciHighA progression following the Fibonacci sequenceA slower progression after a loss
d'AlembertMedium+1 unit after a loss, −1 after a winThe gentlest progression
LabouchereHighA cancellation line; the bet is first + lastMore advanced players and experiments
ParlayMediumThe win stays in play (let it ride)Short runs after a win
1-3-2-6MediumThe positive 1-3-2-6 progression after winsA calmer game riding a winning wave
James BondLow to mediumA flat 20-unit ticket on 25 numbersBroad coverage with no progression
BallyVery high24 numbers with a 12–36–108–324 progressionBlanket bets with a harsh progression
Seven CornersMediumSeven corner bets, 27–28 numbers flatBlanket bets with no progression
System 300Very high34 of 37 numbers, a rare 300-unit lossUnderstanding asymmetric risk
John WayneHighA spread of 18 numbers for 10 unitsCombined bets on numbers
Holy GrailHigh18 distinct numbers with a progressionCovering half the wheel

The name of a system takes you to its page with an interactive test — the current system is highlighted. Want to compare several systems on the exact same sequence of spins? Use the Roulette system tester.

FAQ

Common questions about the James Bond system

Is the James Bond system profitable?

Not in the long run. Even though it covers 25 numbers and wins two spins in three, the expected value is −2.70% of every ticket — the occasional 20-unit loss outweighs the frequent small wins.

How exactly is James Bond bet?

Always the same 20-unit ticket: 14 units on the high numbers 19–36, 5 units on the six line 13–18 and 1 unit on the zero. The spread never changes.

Where does the system come from?

Ian Fleming, the creator of James Bond, described it in the novel Casino Royale (1953). It is a literary story rather than a mathematically verified strategy — which is exactly what made it the most famous “movie” system.

How many numbers does James Bond cover?

On European roulette, 25 of 37 numbers — roughly 67.6%. It loses only on the numbers 1–12. On American roulette the coverage is 25 of 38, because the double zero is not covered.

What does one spin cost?

Always 20 units. At a $10 unit that is $200 a spin — over an hour of live roulette (~60 spins) you stake around $12,000 and hand over roughly $320 of it on average.

Does James Bond work on American roulette?

Considerably worse. The double zero is not covered, there are 13 losing numbers instead of 12, and the average loss per spin doubles from −0.54 to −1.05 units. If at all, then only on a European wheel.

What if I double the whole ticket after a loss?

You create a Martingale with a 20-unit base: 20 → 40 → 80 → 160. Three losses in a row have a 3.4% chance and mean betting eight times the base. You can switch this variant on in the simulator on this page and compare the charts.

What bankroll do I need for James Bond?

A sensible minimum is 50–100 tickets, so 1,000 to 2,000 units. The system does not escalate, but a run of first-dozen results (−20 units a spin) can carve off hundreds of units in a few minutes.

Is James Bond better than a colour bet?

Mathematically they are identical: both have an EV of −2.70%. They differ only in the experience — Bond wins more often, but at a higher price. The choice is purely about which rhythm of play you find more pleasant.

Does James Bond change roulette’s house edge?

No. Each of the ticket’s three bets has a negative expected value, and so does their sum. Arranging chips changes the distribution of results over time, not their average.

Keep going

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First understand the principle, then work out the risk — and test longer scenarios over thousands of spins.